3.7.38 \(\int \frac {1}{\sqrt {x} (2-b x)^{3/2}} \, dx\) [638]

Optimal. Leaf size=16 \[ \frac {\sqrt {x}}{\sqrt {2-b x}} \]

[Out]

x^(1/2)/(-b*x+2)^(1/2)

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Rubi [A]
time = 0.00, antiderivative size = 16, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.062, Rules used = {37} \begin {gather*} \frac {\sqrt {x}}{\sqrt {2-b x}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(Sqrt[x]*(2 - b*x)^(3/2)),x]

[Out]

Sqrt[x]/Sqrt[2 - b*x]

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^(n +
1)/((b*c - a*d)*(m + 1))), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rubi steps

\begin {align*} \int \frac {1}{\sqrt {x} (2-b x)^{3/2}} \, dx &=\frac {\sqrt {x}}{\sqrt {2-b x}}\\ \end {align*}

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Mathematica [A]
time = 0.02, size = 16, normalized size = 1.00 \begin {gather*} \frac {\sqrt {x}}{\sqrt {2-b x}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/(Sqrt[x]*(2 - b*x)^(3/2)),x]

[Out]

Sqrt[x]/Sqrt[2 - b*x]

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Mathics [C] Result contains higher order function than in optimal. Order 9 vs. order 2 in optimal.
time = 2.08, size = 44, normalized size = 2.75 \begin {gather*} \text {Piecewise}\left [\left \{\left \{\frac {1}{\sqrt {b} \sqrt {-1+\frac {2}{b x}}},\frac {1}{\text {Abs}\left [b x\right ]}>\frac {1}{2}\right \}\right \},-\frac {I}{\sqrt {b} \sqrt {1-\frac {2}{b x}}}\right ] \end {gather*}

Warning: Unable to verify antiderivative.

[In]

mathics('Integrate[1/(Sqrt[x]*(2 - b*x)^(3/2)),x]')

[Out]

Piecewise[{{1 / (Sqrt[b] Sqrt[-1 + 2 / (b x)]), 1 / Abs[b x] > 1 / 2}}, -I / (Sqrt[b] Sqrt[1 - 2 / (b x)])]

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Maple [A]
time = 0.11, size = 13, normalized size = 0.81

method	result	size
gosper	\(\frac {\sqrt {x}}{\sqrt {-b x +2}}\)	\(13\)
default	\(\frac {\sqrt {x}}{\sqrt {-b x +2}}\)	\(13\)
meijerg	\(\frac {\sqrt {x}\, \sqrt {2}}{2 \sqrt {-\frac {b x}{2}+1}}\)	\(17\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(-b*x+2)^(3/2)/x^(1/2),x,method=_RETURNVERBOSE)

[Out]

x^(1/2)/(-b*x+2)^(1/2)

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Maxima [A]
time = 0.27, size = 12, normalized size = 0.75 \begin {gather*} \frac {\sqrt {x}}{\sqrt {-b x + 2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-b*x+2)^(3/2)/x^(1/2),x, algorithm="maxima")

[Out]

sqrt(x)/sqrt(-b*x + 2)

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Fricas [A]
time = 0.31, size = 20, normalized size = 1.25 \begin {gather*} -\frac {\sqrt {-b x + 2} \sqrt {x}}{b x - 2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-b*x+2)^(3/2)/x^(1/2),x, algorithm="fricas")

[Out]

-sqrt(-b*x + 2)*sqrt(x)/(b*x - 2)

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Sympy [A]
time = 0.49, size = 41, normalized size = 2.56 \begin {gather*} \begin {cases} \frac {1}{\sqrt {b} \sqrt {-1 + \frac {2}{b x}}} & \text {for}\: \frac {1}{\left |{b x}\right |} > \frac {1}{2} \\- \frac {i}{\sqrt {b} \sqrt {1 - \frac {2}{b x}}} & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-b*x+2)**(3/2)/x**(1/2),x)

[Out]

Piecewise((1/(sqrt(b)*sqrt(-1 + 2/(b*x))), 1/Abs(b*x) > 1/2), (-I/(sqrt(b)*sqrt(1 - 2/(b*x))), True))

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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 50 vs. \(2 (12) = 24\).
time = 0.01, size = 59, normalized size = 3.69 \begin {gather*} -\frac {8 b \sqrt {-b}}{2 \left |b\right | \left (\left (\sqrt {-b \left (-b x+2\right )+2 b}-\sqrt {-b} \sqrt {-b x+2}\right )^{2}-2 b\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-b*x+2)^(3/2)/x^(1/2),x)

[Out]

-4*sqrt(-b)*b/(((sqrt(-b*x + 2)*sqrt(-b) - sqrt((b*x - 2)*b + 2*b))^2 - 2*b)*abs(b))

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Mupad [B]
time = 0.30, size = 12, normalized size = 0.75 \begin {gather*} \frac {\sqrt {x}}{\sqrt {2-b\,x}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^(1/2)*(2 - b*x)^(3/2)),x)

[Out]

x^(1/2)/(2 - b*x)^(1/2)

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